(24x^2)-640=0

Solution for (24x^2)-640=0 equation:

(24x^2)-640=0

a = 24; b = 0; c = -640;
Δ = b2-4ac
Δ = 02-4·24·(-640)
Δ = 61440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{61440}=\sqrt{4096*15}=\sqrt{4096}*\sqrt{15}=64\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64\sqrt{15}}{2*24}=\frac{0-64\sqrt{15}}{48}
=-\frac{64\sqrt{15}}{48}
=-\frac{4\sqrt{15}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64\sqrt{15}}{2*24}=\frac{0+64\sqrt{15}}{48}
=\frac{64\sqrt{15}}{48}
=\frac{4\sqrt{15}}{3}
$